Maxima of difference between Primes!

Let a , b , c , ( a + b c ) , ( a + c b ) , ( b + c a ) , ( a + b + c ) a, \ b, \ c, \ (a+b-c), \ (a+c-b), \ (b+c-a), \ (a+b+c) be seven distinct prime numbers such that the sum of two of a , b , c a,b,c is 800. Let d d be the difference between the largest and the smallest numbers among the seven primes. Find the largest possible value of d d .


The answer is 1594.

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1 solution

Johnny Nicholson
Aug 29, 2015

(sketch) Wlog a>b>c. Now a+b+c is the largest and b+c-a<c and so is the smallest. Hence, d=(a+b+c)-(b+c-a)=2a. But a<b+d<=800 and then a=797 works (as 800-797=3 is indeed a prime). Hence d=2*797=1594.

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