Maximum Angle

Geometry Level 2

In triangle A B C ABC , the three sides are A B = 2 \overline{AB}=2 , B C = 4 \overline{BC}=4 and C A = x . \overline{CA}=x. When angle C C is at its maximum, what is the value of x 2 ? x^2?

13 14 12 15

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2 solutions

Kumar Gupta
Apr 23, 2014

When angle C is at a maximum, then cos C \cos \angle C is at a minimum.

By cosine rule, we have cos C = x 2 + 4 2 2 2 2 × x × 4 = x 2 + 12 8 x \cos \angle C = \frac{ x^2 + 4^2 - 2^2 } { 2 \times x \times 4 } = \frac{ x^2+12 } { 8x } .

By AM-GM (or calculus), we know that the minimum of this occurs when x 2 = 12 x^2 = 12 .

Ashutosh Sharma
Apr 27, 2014

We may consider point B at origin. Let BC lie on +ve x-axis. So A must lie on a circle with radius 2 centered at origin . When AC is tangent to this circle Angle C will be maximum. And angle A will be 90. AB=2 BC=4, Just apply Pythagoras theorm

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