Two small spheres of mass each are connected to each other by means of an unstretched spring of force constant and natural length .
The system is placed on a smooth horizontal surface and the two spheres are given velocity as shown in the figure below. The maximum elongation in spring is found to be during subsequent motion.
Calculate in . Take .
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Let the maximum elongation in the spring be x .
Conserving the angular momentum about C.M, we get
v 2 l = ( l + x ) u
given, x = 0 . 4
l = 2 . 4
u = speed of the sphere in C.M frame at maximum elongation
By applying conservation of energy, we get
2 2 m v 2 = 2 1 ( 2 m ) ( 2 2 v ) 2 + 2 2 m u 2 + 2 k x 2 .
Solving this equation we get v = 5 m / s .