Maximum may be?
Algebra
Level
pending
What is the maximum value of the expression,
3^99
2^100
1258788890099373882222
123456789101112131000
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1 solution
Given that a+b+c.....+x=100.., so 100 such numbers should add up to 100,so we can deduce that for a,b,c,....x to be maximum and yet sum to 100,they should be equal to 1..i .e a=b=c=....=x=1. So the max value of the expression is 2^100.