Maximum sum power of cubic

Algebra Level 5

{ a + b + c + d + e + f = 6 a 2 + b 2 + c 2 + d 2 + e 2 + f 2 = 36 5 \large{ \begin{cases} a+b+c+d+e+f=6 \\ a^2+b^2+c^2+d^2+e^2+f^2=\frac{36}5 \end{cases}}

Let a , b , c , d , e a,b,c,d,e and f f be positive real numbers such that the system of equations above are fulfilled. If the maximum value of

a 3 + b 3 + c 3 + d 3 + e 3 + f 3 a^3+b^3+c^3+d^3+e^3 + f^3

can be expressed as x y \dfrac xy for coprime positive integers x x and y y , find the value of x + y \sqrt{x+y} .


The answer is 17.

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1 solution

s o x + y = 264 + 25 = 17 so \sqrt{x+y} = \sqrt{264+25} = \boxed{17}

I you will permit me to nitpick, the 2 problems differ in that, in the one you posted, you are looking for the maximum, so you need to show that equality can be achieved (which as far as I can tell, you have not done). I'm curious what values a, b, c... take at the maximum.

Joe Mansley - 2 years, 11 months ago

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