Maximum Terms satisfying a special property

We have a series where the sum of any 7 7 consecutive terms is negative and the sum of any 11 11 consecutive terms is positive. What is the maximum number of terms in this series?


The answer is 16.

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2 solutions

Yash Singhal
Nov 11, 2014

The maximum number of terms is given by the formula m + n g c d ( m , n ) 1 m+n-gcd(m,n)-1

Here, let m = 11 m=11 and n = 7 n=7 and g c d ( 7 , 11 ) = 1 gcd(7,11)=1

So, putting this information in the formula above, we get the answer as 16 \huge{16} .

Please explain this formula? Where does it come from?

A Former Brilliant Member - 6 years, 7 months ago
Anatoliy Razin
Nov 17, 2014

16 \boxed{16} elements:

5 , 5 , 13 , 5 , 5 , 5 , 13 , 5 , 5 , 13 , 5 , 5 , 5 , 13 , 5 , 5 5, 5, -13, 5, 5, 5, -13, 5, 5, -13, 5, 5, 5, -13, 5, 5

for 17 17 elements we review table

a 1 , a 2 , . . . . , a 11 a_1, a_2, ...., a_{11}

a 2 , a 3 , . . . . , a 12 a_2, a_3, ...., a_{12}

....................................

a 7 , a 8 , . . . . , a 17 a_7, a_8, ...., a_{17}

each row is positive and each column is negative so we cannot define total sum

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