Maxing out

Algebra Level 3

{ x + 2 y < 30 3 x + y < 26 \large{ \begin{cases}x + 2y < 30 \\ 3x+ y < 26 \end{cases}}

Let x x and y y be positive integers satisfying the system of inequality above.

Let the largest possible value of x x be U U and the largest possible value of y y be V V .

(Obviously, if x = U x = U , y y cannot simultaneously be equal to V V .)

Find U + V U + V


The answer is 22.

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1 solution

Denton Young
Jul 23, 2016

The largest value of x x occurs when y = 1 y = 1 . Then x = 8 x = 8 is the maximum, so U = 8 U = 8

The largest value of y y occurs when x = 1 x = 1 . Then y = 14 y = 14 is the maximum, so V = 14 V = 14

8 + 14 = 22

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