mbs1

Algebra Level 3

f ( x ) = a x 2 + b x + c f(x)=ax^2+bx+c is a quadratic polynomial with a, b, and c as real numbers. α \alpha and β \beta are real and roots of f ( x ) f(x) . It is given that α < 1 \alpha < -1 and β > 1 \beta > 1 . What is the sign of the expression 1 + c a + b a 1+\frac{c}{a}+|\frac{b}{a}|

Negative Positive

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

X X
Jul 28, 2018

This expression = 1 + α β + α + β =1+\alpha\beta+|\alpha+\beta|

If α + β > 0 \alpha+\beta>0 ,then it becomes ( 1 + α ) ( 1 + β ) (1+\alpha)(1+\beta) which is negative.

If α + β < 0 \alpha+\beta<0 ,then it becomes ( 1 α ) ( 1 β ) (1-\alpha)(1-\beta) which is also negative.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...