Mean of Normal Distribution

Probability Level 1

What is the mean of the normal distribution given by:

$\large f(x)=\frac{1}{\sqrt{4\pi}} e^{-\frac{(x-1)^2}{4}}?$

1

2

4

\sqrt{2}

1 solution

Matt DeCross
Apr 20, 2016

Recall that the normal distribution is:

$f(x) = \frac{1}{\sqrt{2\pi\sigma^2}} e^{-\frac{(x-\mu)^2}{2\sigma^2}}.$

Reading off the values, one can see that $\sigma^2 = 2$ is the variance and $\mu = 1$ is the mean.