Mean question?

What is the smallest positive integer that is equal to the eighth power of the geometric mean of its four prime divisors?


The answer is 44100.

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1 solution

Arjen Vreugdenhil
Feb 10, 2016

Let the prime factorization of the number be N = p 1 e 1 p 2 e 2 p 3 e 3 p 4 e 4 . N = p_1^{e_1}\cdot p_2^{e_2}\cdot p_3^{e_3}\cdot p_4^{e_4}. The eighth power of the geometric mean of { p 1 , p 2 , p 3 , p 4 } \{p_1, p_2, p_3, p_4\} is N = ( p 1 p 2 p 3 p 4 4 ) 8 = p 1 2 p 2 2 p 3 2 p 4 2 . N = \left(\sqrt[4]{p_1\cdot p_2\cdot p_3\cdot p_4}\right)^8 = p_1^2\cdot p_2^2\cdot p_3^2\cdot p_4^2. The smallest number with this structure is, of course, that with the smallest values of p p : N = 2 2 3 2 5 2 7 2 = 21 0 2 = 44100 . N = 2^2\cdot 3^2\cdot 5^2\cdot 7^2 = 210^2 = \boxed{44100}.

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