What is the smallest positive integer that is equal to the eighth power of the geometric mean of its four prime divisors?
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Let the prime factorization of the number be N = p 1 e 1 ⋅ p 2 e 2 ⋅ p 3 e 3 ⋅ p 4 e 4 . The eighth power of the geometric mean of { p 1 , p 2 , p 3 , p 4 } is N = ( 4 p 1 ⋅ p 2 ⋅ p 3 ⋅ p 4 ) 8 = p 1 2 ⋅ p 2 2 ⋅ p 3 2 ⋅ p 4 2 . The smallest number with this structure is, of course, that with the smallest values of p : N = 2 2 ⋅ 3 2 ⋅ 5 2 ⋅ 7 2 = 2 1 0 2 = 4 4 1 0 0 .