The smallest six positive even integers are
2 , 4 , 6 , 8 , 1 0 , 1 2 .
What is their mean?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
The mean of a series of numbers = T o t a l n u m b e r o f t h e d a t a v a l u e s S u m o f t h e d a t a v a l u e s So for this problem, m e a n = 6 2 + 4 + 6 + 8 + 1 0 + 1 2 ⇒ m e a n = 6 4 2 ⇒ m e a n = 7
no need to add all terms,, co number of terms is even. so take middle pair such as 6,8. so 7 is the middle value.. but it is possible where there is arthematic progression
HELLO, WE KNOW THAT MEAN = SUM OF THE GIVEN TERMS / NUMBER OF TERMS. SO 2+4+6+8+10+12 / 6 SO WE GET 7. BY THIS THE MEAN OF THE DATA IS 7.
why divided by 6 ?
2+4+6+8+10+12=42 divide 42/6 why only 6 because there are totally 6 numbers
First, you add 2+4+6+8+10+12, and you get 42. Then you divide 42 by 6, and you get 7. The correct answer is 7.
2+4+6+8++10+12=42 divide by its count which is 6 so the result is 7
(2+4+6+8+10+12) / 6 = 42 / 6 = 7
take middle pair such as 6&8. so answer is 7
Problem Loading...
Note Loading...
Set Loading...
2+4=6 6+6=12 12+8=20 20+10=30 30+12=42 42/6=7