The error in the measurement of the radius of a sphere is 0.6%. What is the permissible error in the measurement of surface area (in percentage)?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Surface area of sphere is 4 π r 2 .
Since 4 and π are constants, we will take the limit of errors for radius only.
Using formula of powers for finding errors we get ( 0 . 6 ) × 2 = 1 . 2 % .
( Error in nth power is n times the error )