Mechanics level one

Classical Mechanics Level 3

A rod can slide between two perpendicular wall at x and y axis.If the end A( x axis) moves to the right with speed v,then find the speed of the rod in terms of deta,where deta is the angle between the ladder and the x axis,consider v=5m/s,deta=45 degree.


The answer is 3.54.

Aneesh Kumar by Aneesh Kumar , 22, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

The point whose speed is required should be mentioned. Let this point be the C.M. of the rod. Now, let β be the angle that the rod makes with the x axis. Then the velocity of the lower end of the rod is v=-lsinβ d β d t \dfrac{dβ}{dt} . This implies d β d t \dfrac{dβ}{dt} =- v l s i n β \dfrac{v}{lsinβ} . The position coordinates of the C.M. of the rod are ( l 2 \dfrac{l}{2} cosβ, l 2 \dfrac{l}{2} sinβ). Therefore the speed of the C.M. of the rod is v 2 \dfrac{v}{2} cosecβ. Substituting the values, we get the magnitude of the speed as 5 √ 2 \dfrac{5}{√2} =3.5355

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...