A 20g bullet strikes a fixed block of wood at a speed of 320 m/s [fd]. The bullet embeds itself in the block of wood to a depth of 6.0 cm. Calculate the average net force acting on the bullet while it is being brought to rest in N [fd]. Answer to the correct number of significant figures.
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Average acceleration is − 2 × 0 . 0 6 3 2 0 2 ≈ − 8 5 3 3 3 3 . 3 3 3 3 m/s 2 . So the average force is ≈ 0 . 0 2 × ( − 8 5 3 3 3 3 . 3 3 3 3 ) ≈ − 1 7 0 6 6 . 6 7 N