Meddling with velocities!

An object is dropped from rest from a height of h h . What is the velocity of the object in the middle of its journey, i.e. when the object is at half its original distance to its destination?

g h gh 2 g h 2gh 2 m g h 2mgh g h \sqrt{gh} 2 g h \sqrt{2gh} 2 m g h \sqrt{2mgh}

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1 solution

Joshua Chin
Jan 2, 2016

Due to conservation of total mechanical energy,

Δ G P E = K E f \Delta GPE\quad =\quad { KE }_{ f }

m g Δ h 2 = m v 2 2 \frac { mg\Delta h }{ 2 } =\frac { m{ v }^{ 2 } }{ 2 }

which simplifies to

v = g h v=\sqrt { gh }

The solution is wroght. 5 answer is right :(

sergio llorente - 10 months, 1 week ago

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@sergio llorente Nope. That's the velocity when the ball hits the ground. The velocity when the ball is halfway from the ground is half of that.

Krishna Karthik - 4 months, 3 weeks ago

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