Medians to Area of Square

Geometry Level 2

Δ A B C \Delta ABC is a right triangle with C = 9 0 . \angle C = 90^{\circ}.

A M = 25 AM=25 and B N = 20 BN=20 are two medians of Δ A B C \Delta ABC .

Find the area of the square A B E F ABEF .


The answer is 820.

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1 solution

Aaryan Maheshwari
Dec 14, 2017

Median divides side into 2 equal halves. Let B C = x BC=x and A C = y AC=y .

Then,from question, x 2 + ( y 2 ) 2 = 2 5 2 x^2+\left(\frac{y}{2}\right)^2=25^2 y 2 + ( x 2 ) 2 = 2 0 2 y^2+\left(\frac{x}{2}\right)^2=20^2 Adding the two equations gives: 5 x 2 4 + 5 y 2 4 = 1025 \frac{5x^2}{4}+\frac{5y^2}{4}=1025 5 4 ( x 2 + y 2 ) = 1025 \Rightarrow\space \frac{5}{4}(x^2+y^2)=1025 Area of square ABEF = ( x 2 + y 2 ) 2 = x 2 + y 2 = 1025 × 4 5 = 820 \therefore\space \text{Area of square ABEF}=(\sqrt{x^2+y^2})^2=x^2+y^2=1025\space \times\space \frac{4}{5}=\boxed{820}

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