Medium Portion

The three medians divide the triangle into six smaller triangles of equal area. Since the yellow area has $2$ triangles, the area of one triangle is $\dfrac{47}{2}=23.5$ . The blue area has $4$ triangles, so the area of the blue area is $4(23.5)=$ $\boxed{94}$

Medians divide the triangle in six triangles of the same area. The yellow area covers two of the six triangles of the same area $\therefore$ the blue area is twice than yellow area $\Rightarrow$ the blue area is $47\times 2=94$

$\triangle AOB$ and $\triangle ACB$ have the same base, $AB$ , and their heights are in proportion $3:1$ since $CF=3\times OF$ .

Area $[ABC]=3\times\color{#CEBB00}[AOB]$

$\color{#3D99F6}[blue]$ $=[ABC]-\color{#CEBB00}[AOB]$ $=2\times\color{#CEBB00}[AOB]$ $=2\times47=\boxed{94}$

Actually medians divide $\triangle ABC$ into six triangles of equal area, in this case four of them are blue and two yellow.