Meeting between tangent and secant.

Geometry Level 3

PT is tangent to the circle with center O.

If PT = 8 and PA = 2 , then PB = ?

This problem is a part of the sets - 1's & 2's & " G " for geometry .


The answer is 32.

View wiki
Sakanksha Deo by Sakanksha Deo , 23, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Jahnvi Verma
Mar 14, 2015

(PT)^2=PA PB by AA similarity Therefore 2 PB=64 PB=32

1 Helpful 0 Interesting 0 Brilliant 0 Confused

By the power of a point (tangent-secant form), we have

P A ( P B ) = ( P C ) 2 PA(PB)=(PC)^2

2 ( P B ) = 8 2 2(PB)=8^2

P B = 32 PB=32

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...