Can you do mensuration?

Geometry Level 2

In parallelogram $ABCD$ , $AB = 6$ , $BC = 5$ and $AC = 7$ .

Find the perpendicular distance between $AB$ and $CD$ .

25

2\sqrt6

2\sqrt8

3\sqrt6

5 solutions

Sachin Sharma
Oct 29, 2015

There is some typing mistake in the question and it should be "the perpendicular distance between AB and CD " instead of AB and AC .

Debmeet Banerjee
Nov 14, 2015

Simple question. First make a near diagram. Use heron's formula to find area of triangle ABC. The area of this will be equal to 1/2* AB*perpendicular distance between AB and DC. Since the base is given in the question, the unknown can be found out easily!!!!!!!;

Kevin Rice
Nov 21, 2015

By heron's formula, s=a+b+c)/2, or for this problem s=(6+5+7)/2, or 9. Now area=sqrt(s(s-a)(s-b)(s-c)), or for this problem area=sqrt(9(3)(4)(2)). A is 6, as this is the base. Now we get that the area=sqrt(216) or 6sqrt (6). Since area=bh/2, and we know base=6, our equation becomes 3h=6sqrt(6). Simplify this to h= 2*sqrt(6) I'm sorry syntax doesn't seem to be working for me.

Gopal Narayanan
Oct 31, 2015

Distance from ab to cd. Find angle cosine of abc. Then ht is 5 * sine of angle abc

Asif Mujawar
Oct 29, 2015

Options are not given correctly

2 * SQRT 6 = 4.97493718553 <> 4.97493718553 = SQRT (24.75)

John Wyatt - 5 years, 7 months ago

Can you do mensuration?

5 solutions

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