mensuration is hard...

Geometry Level 2

If the perimeter and radius of a sector are 38 and 9 cm respectively . find its area.


The answer is 90.

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1 solution

The length of the circular arc is 38 9 9 = 20 c m 38-9-9=20~cm . The formula for the length of a circular arc is c = θ 360 ( 2 π r ) c=\dfrac{\theta}{360}(2\pi r) where θ \theta is the central angle and r r is the radius. Substituting we get

20 = θ 360 ( 2 π ) ( 9 ) 20=\dfrac{\theta}{360}(2\pi)(9)

θ 127.32 \theta \approx 127.32

The area of a circular sector is given by A = θ 360 π r 2 A=\dfrac{\theta}{360}\pi r^2 , substituting, we get

A = 127.32 360 × π ( 9 2 ) = 90 A=\dfrac{127.32}{360} \times \pi (9^2) =\boxed{90}

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