Mental Math

To determine their distance from each other, we need to measure their distance from the same point of reference. Person A is now 140m away from their starting point. Person B is now 100m away from their starting point. We now need a common point of reference. We know they were 200m apart from their initial starting points, and because $200-100=100$ , this means Person B is now 100m away from Person A's start point.

Since we now know their distance from the same point, let's determine the difference:

$140 - 100 = \boxed{40}$

B travels 60+20+40+20 (to get back to the actual path) = 140 m. Since both A and B are travelling at the same speed, A also travels 140 m. Out of what B travelled, the first link (60 m) and the 3rd link (40 m) was in the direction of the actual path, so B will arrive back on the actual path at 100 m point. But A walked towards B 140 m in the meantime, so A is passed the point of return of B by 40 m. Hence they would 40 m apart.

A travelled=140m B travelled=100m A-B=distance between A and B distance between A and B = 140m -100m= 40m

B walks a total of 100 m toward A. But he also walks 40 m in a different direction. So he walks 100 m on the line of measurement. A walks all his distance in that direction, so he actually passes B's position and goes to the 140 m position, because B went 40 m not on the line of measurement.

You can think of it as B starts off at 0.0, and A starts at 200 on the number line. B ends up at 100, and A ends up at 60. So they are 40 m apart.

B can walk 140m in the time he took to get back to the road. Since A and B both walked at the same speed, A also walked 140m, in a straight line. A ends up 140m closer to where B started, while B has only walked 100m closer to where A started, due to the 40m detour off the road and back. A is at position 140, and B is at position 100. 140 - 100 = 40m distance between A and B

A travels 140 m and B travels first 60 and then go back 40 so he covers 20 m. now add total distance cover by the A and B which is 160m now subtract the the distance cover by the A and B into Total Distance. 200-160= 40m.

initially separated by 200m , lets say A moved by x m towards B and it is given that B moved by 60 m towards A. now, the separation is 140m between the two original position held by A and the current position of B. Now, A has moved by a distance x and therefore the separation between the two is (140 - x) .from that instant, B turned left and moved 20 m ,then turned right and moved 40 m and again turned right and returned back to the same road hence forming a rectangle of of 2 sides of 20m and 2 sides of 40 and 140-x m respectively. the other two sides must be equated to get the value of x ...and hence the value of 140-x will give the required answer since both are travelling at the same speed

.:. 200-60-20-(40+40)=40m

The answer is null. Information was insufficient by not including the displacement/distance of A

since A & B are moving with the same speed, B moved 60 m + 20 m + 40 m + 20 m =140 meters, lets say that B moved them in 60 seconds, then Person A moved 140 meters in 60 seconds, and since person B moved in the straight line of the motion only 60 m + 40 m = 100 meters, Therefor the distance between A & B is 40 meters.

A and B both travelled 140 meters. However, B had take some turns while moving towards each other. To consider, B had travel at about 100 meters straight line and A had travel 140 meters straight line...

the solution would be:

140 meters - 100 meters = 40 meters

<----------60m----------> "A" 60+40M <-------------60m-------> | _ |40m

240-200=40

when , a= (0+60 + 20 + 40)=120m , thats time B is =(200-60-20+40)=160m . after B go to 40 meter back for initial position = 200m and that time A=(120+40)=160m . so, B - A= 200 - 160 = 40m

Both cover 240 meters combined so, 240-200=40 that's the answer