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Geometry Level 1

In the figure, let

a = P S Q B R T B R T P S Q , b = Z V Y W X C W Z V X C Y . a = \dfrac{PS\cdot QB\cdot RT}{BR\cdot TP\cdot SQ},\quad b =\dfrac{ZV\cdot YW\cdot XC}{WZ\cdot VX\cdot CY}.

What is the value of a b ? a-b?


The answer is 0.

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2 solutions

Tan Ho
Aug 9, 2015

More simply, a and b are equal. Just check each element: PS corresponds to ZV, QB to XC, RT to YW etc. Therefore a=b and a-b=0.

Siddharth Singh
Jun 27, 2015

We can use Menelaus theorem.

a = P S S Q Q B B R R T T P = 1 a=\frac{PS}{SQ}*\frac{QB}{BR}*\frac{RT}{TP}=-1

b = Z V V X X C C Y Y W W Z = 1 b=\frac{ZV}{VX}*\frac{XC}{CY}*\frac{YW}{WZ}=-1

Thus

a b = ( 1 + 1 ) = 0 a-b=(-1+1)=\boxed0

shouldn't a = 1 and b =1 ?

frank guo - 4 months, 3 weeks ago

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