Messed up the AGES.....
Number Theory
Level
2
Two years ago, Satvik was three times as old as his son.
Two years hence, twice his age will be equal to five times that of his son.
What is the present age of Satvik ?
The answer is 38.
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Consider x as Satvik's present year and y as his son's present year. 2 years ago, Satvik was 3 times older than his son : (x-2) = 3(y-2). 2 years hence, twice his age will be five times that of his son : 2(x+2) = 5(y+2). Now, you just have to solve the system of equations and the solution will be x=38.