Metallic solid sphere

A metallic solid sphere with radius R is given the charge Q . Q. If r r denotes the distance from the center of the sphere, which of the following statements is true?

The electric field is not perpendicular to the surface of the sphere. The charge Q is not on the outer surface of the sphere. The electric filed is given by Q 2 π ε 0 r 2 \dfrac{Q}{2\pi\varepsilon_{0}r^{2}} for r > R . r>R. The electric field is zero for 0 < r < R.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Charge stays on the surface of a conductor sphere, therefore the electric field within the sphere is 0 (the answer). Due to the symmetry, the electric field lines are perpendicular to the sphere surface and its magnitude is given by: E = Q 4 π ϵ 0 r 2 E=\dfrac{Q}{4\pi\epsilon_0 r^2} for r > R r>R .

According to my knowledge it is inversely proportional to the square of r

Aryan Pandey - 3 years, 1 month ago

Log in to reply

Yes, you are right.

Chew-Seong Cheong - 3 years, 1 month ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...