Michael and Betty play a game...

Michael and Betty play a game with a fair n n -sided die whose faces are numbered as 1 , 2 , 3 , . . . , n 1,2,3,...,n . In this game, Michael is assigned a value m m and Betty is assigned a value b b , both also in the range. Michael and Betty take turns rolling the die; Michael goes first.

If Michael rolls a number less than or equal to m m , the game ends and he wins. If Betty rolls a number less than or equal to b b , the game ends and she wins. The game continues until one player wins.

Suppose m = b m=b , who has an advantage?

None; 50% Betty Michael

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1 solution

Blan Morrison
Oct 19, 2018

Since Michael goes first, he clearly has the upper hand. If Michael has rolled his die r r times, then Betty has had a chance to win r 1 r-1 times. Therefore, Michael has a greater chance of winning. β ~\beta_{\lceil \mid \rceil}

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