Midpoints of the Sides (Between the Lines of Geometric Brilliance)

Geometry Level 3

Let A B C D ABCD be a quadrilateral. Let M 1 , M 2 , M 3 , M_1 , M_2, M_3, and M 4 M_4 be the midpoints of sides AB, BC, CD, DA, respectively. Given that M 1 M 2 = 5 M_1M_2 = 5 and M 2 M 3 = 25 M_2M_3 = 25 , find the perimeter of quadrilateral M 1 M 2 M 3 M 4 M_1M_2M_3M_4 .


The answer is 60.

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1 solution

Alan Yan
Aug 10, 2015

Lemma: The midpoints of a quadrilateral form a parallelogram.

Proof: M 1 = A + B 2 ; M 2 = B + C 2 ; M 3 = C + D 2 ; M 4 = D + A 2 \vec{M_1} = \frac{\vec{A}+\vec{B}}{2} ; \vec{M_2} = \frac{\vec{B} + \vec{C}}{2} ; \vec{M_3} = \frac{\vec{C}+\vec{D} }{2} ; \vec{M_4} = \frac{\vec{D}+\vec{A}}{2} Through simple computations, it is easy to proof that M 1 M 2 = M 3 M 4 \vec{M_1M_2} = \vec{M_3M_4}

Therefore the side lengths of the parallelogram must be 5, 25, 5, 25 which implies a perimeter of 60.

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