Miles moving company

Let's get this in brief. He has to carry $25$ books, $4$ at a time. Let's get to every trip-

$\quad{ }$ TRIP $\quad{ }$ TOTAL BOOKS TRANSPORTED

$1^{st}$ trip- 4

$2^{nd}$ trip 8

$3^{rd}$ trip 12

$4^{th}$ trip 16

$5^{th}$ trip 20

$6^{th}$ trip 24

$7^{th}$ trip 25

Therefore, total trips that he had to take are $\fbox{7}$ .

Since Miles can carry $4$ books in $1$ trip to auditorium ,

Thus he can carry $24$ books in $6$ trips .

But one book will be left ,

Thus , he has to take $1$ round more for $1$ more book that is left.

Therefore total rounds = $\boxed{7}$

This is the basic idea of Pigeon hole principle.

If miles can carry up to 4 books. 4 x 6 = 24 24 + 1 (only one left) = 25 6 + 1 = 7 times

Clearly , 25 is not divisible by 4. the biggest no. after 25 divisible by 4 is 24.now 24/4 = 6.So, he needs 6 trips to transport 24 books. hence he needs at least on trip more to carry 25 book, that is 6+1 = 7.

Miles is given the task of transporting 25 books from classroom to the auditorium

at one time he can transport four books

so....

he has to make 6 trips to transport 24 books

for the remaining 1 book he has to make 1 another trip

so the minimum no.of trips is 7

4 x 6 = 24

He would be left with 1 book after 6 trips.

So, he has to do one more trip.

So, total number of trips = 6+1 = 7.

Sabendo que: D = d . q + r; temos: 25 = 4 . 6 + 1. Com isso,

6 viagens + 1 viagem = 7 viagens!!

25/4=6.25

  =7