Mind Warmups-2

$T(n)$ doesn't contain $6$ or an integral multiple of $6$ if and only if $n \equiv 1 \pmod{6}$ , and $\frac {1}{6}$ of the $96$ sets are like this, so the number of sets that satisfy the condition mentioned in the problem is $\frac {5}{6} \times 96 = \boxed{80}$

Easy way put n=1 to 12 so all numbers from 1 to 12 except 1and 7 satisfy conditions. So for 12 no's there are 10 no's req. For 96 it will be 80.