Min ( f ) (f) =Min ( f ( f ) ) (f(f))

Algebra Level 3

Consider the quadratic function f ( x ) = x 2 + 8 x + a . f(x)=x^2+8x+a. If the minimum value of f ( x ) f(x) is the same as the minimum value of f ( f ( x ) ) f(f(x)) , what is the maximum value of the real number a a ?

12 15 14 13

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1 solution

Tom Engelsman
Nov 7, 2020

The function f ( x ) = x 2 + 8 x + a = ( x + 4 ) 2 + ( a 16 ) f(x)=x^2+8x+a = (x+4)^2 + (a-16) attains its minimum value of a 16 a-16 at x = 4. x=-4. The composite function:

f ( f ( x ) ) = ( x 2 + 8 x + a ) 2 + 8 ( x 2 + 8 x + a ) + a = [ ( x 2 + 8 x + a ) + 4 ] 2 + ( a 16 ) f(f(x)) = (x^2+8x+a)^2 + 8(x^2+8x+a) + a = [(x^2+8x+a)+4]^2 + (a-16)

has the same minimum value as f ( x ) f(x) when the quantity x 2 + 8 x + ( a + 4 ) = 0 a = x 2 8 x 4 = ( x + 4 ) 2 + 12 a M A X = 12 . x^2 + 8x + (a+4) = 0 \Rightarrow a = -x^2-8x-4 = -(x+4)^2 +12 \Rightarrow \boxed{a_{MAX} = 12}.

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