Mini problem

Geometry Level 2

cos [ sin 1 ( 7 11 ) + sec 1 ( 11 7 ) ] \cos\left[\sin^{-1}\left(\frac{-7}{11}\right)+\sec^{-1}\left(\frac{-11}{7}\right)\right]

Evaluate the expression above.


The answer is 0.00.

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1 solution

Vishnu Bhagyanath
May 17, 2015

c o s [ s i n 1 ( 7 11 ) + s e c 1 ( 11 7 ) ] cos [ sin^{-1}(\frac{-7}{11}) + sec^{-1}(\frac{-11}{7})] c o s [ s i n 1 ( 7 11 ) + c o s 1 ( 7 11 ) ] cos [ sin^{-1}(\frac{-7}{11}) +cos^{-1}(\frac{-7}{11})] c o s [ θ + ( 90 θ ) ] cos [\theta + (90-\theta)] = c o s ( 90 ) = 0 =cos(90) = 0

Moderator note:

Careful there, you're implying that s i n 1 ( 7 11 ) = θ sin^{-1}(\frac{-7}{11}) = \theta and c o s 1 ( 7 11 ) = 90 θ cos^{-1}(\frac{-7}{11}) = 90 - \theta . Checking with a scientific calculator shows that they don't satisfy both equations at the same time.

Do you know why? Because you have committed a fallacy. Can you find what fallacy that is?

How did you consider them as complementary angles?

Sameer Alam - 4 years ago

To challenge master: If we let θ = sin 1 7 11 \theta = -\sin^{-1}\frac{7}{11} , then everything checks out. Could you explain what the fallacy is? I don't understand.

John Frank - 3 years, 9 months ago

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