Minimum number of digit 3 required be And minimum no. Of continuos functions required be . To operate them in such a way that the answer will be . Note : Only number ' ' can be used . Eg . =2 Here and signum functions are used. But in orignal function should be continuos. Its original. Ans should be
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\log_\sqrt{3} 3= 2 Here two functions are used root and log. And two 3's. Hence a + b = 4