Ω = ( 1 + R a r a ) ( 1 + R b r b ) ( 1 + R c r c )
Let P be a point inside an equilateral triangle A B C , and let R a , R b , R c and r a , r b , r c denote the distances of P from the vertices and edges, respectively, of the triangle. Find the minimum value of Ω .
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(I'll write a better solution when I can think of one.)
The usual strategy for this kind of problems is to use the equality case, i.e. when 1 + R a r a = 1 + R b r b = 1 + R c r c .
That leaves us with the central point,where all the ratios are 1:2, because the centroid divides medians into 1:2 ratios.