Minimum distance to the surface of an ellipsoid

Given the ellipsoid

$\dfrac{x^2}{10^2} + \dfrac{y^2}{15^2} + \dfrac{z^2}{30^2} = 1$

and the point $P = (10, 15, 30$ ), determine the minimum distance $d^*$ from $P$ to the surface of the ellipsoid. If $Q = (x_1, y_1, z_1)$ is the point on the surface of the ellipsoid that is closest to $P$ , then submit the value of $\lfloor 100 (x_1 + y_1 + z_1 + d^* ) \rfloor$ , where $\lfloor \cdot \rfloor$ is the floor function, for example $\lfloor 2.8 \rfloor = 2$ .