Minimum Information Sum

Algebra Level 2

Alice has written on a piece of paper a sequence of numbers, 13 , 16 , 19 , 22 , 13, 16, 19, 22, and 25 , 25, in that order. She keeps the paper hidden from Bob.

Alice tells Bob that there are exactly 5 numbers, written in order of magnitude, and the differences between adjacent terms are all the same.

Alice asks Bob to guess the sum of the numbers. She will allow Bob to ask for any of the numbers as a hint. What is the fewest number of hints Bob would need to correctly guess the sum?

1, he should ask for just the middle term 2, he should ask for the smallest and largest terms 5, he should ask for all five numbers

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1 solution

Abidur Rahman
Jun 3, 2017

If he knows that the difference between each consecutive term is the same and that there are five numbers, then he only needs the middle term as the sequence can be described like this: n - 2x, n - x, n, n + x, n + 2x, where n = 19. This simplifies to 5n, or 5 x 19 = 95.

If there were six numbers, again he would need the middle term, but this time it would be a decimal as the median of 6 numbers requires you to find the (6+1)/2 term i.e the 3.5th term.

(All the xs cancel out i.e. -2x +2x =0, -x + x =0)

To the two commenters. Bob doesn't need to know the difference. As per the comment, if the middle number is n and d is the difference then the sum is n-2d + n-d + n + n + d + n + 2d. All the ds cancel and the result is based only on n. The sum is 5n.

Andy Gregory - 3 years, 11 months ago

If there were six numbers, he would need at least 2 2 numbers known to find the sum. :)

Jaydee Lucero - 3 years, 11 months ago

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Yh, he would need two numbers

Abidur Rahman - 3 years, 11 months ago

But bob does not know the difference. Therefore, 2 questions needed for the answer.

Matt A - 3 years, 11 months ago

Bob does not know x. Therefore knowing n only is not sufficient to determine the sum.

Bruce Fulton - 3 years, 11 months ago

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