minimum number

Find the last digit is 7 and which becomes 5 times larger when this lastmdigit is carried to the beginning of this number.


The answer is 142857.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Unit digit is 7. After operation,{ that is multiplying by 5 and shifting 7 to fist position,} 7 * 5=35, so unit digit must be 5. So the last two digits would be 57. Go to logical solution. \text{Unit digit is 7. After operation,\{ that is multiplying by 5 and} \\ \text {shifting 7 to fist position,\} 7 * 5=35, so unit digit must be 5.} \\ \text{So the last two digits would be 57.} \\ \color{#D61F06}{\text{Go to logical solution.} }\\ ~ 57 * 5=285. So let us take the number as 2857. 7285/5=1457 and not 2857. So next step. 2857 * 5=14285 . So let us take the number as 142857. 142857 * 5=714285 so this is the number. \\ \text{ 57 * 5=285. So let us take the number as 2857.}\\ \text{7285/5=1457 and not 2857. So next step.}\\ \text{2857 * 5=14285 . So let us take the number as 142857.} \\ \text{142857 * 5=714285 so this is the number. } \\

I do not know how this works. But this is a special number!!! 142857 1 , 142857 2 , 142857 3 , 142857 4 142857 5 142857 6 all have the same digits shifted!!! But 142857 * 7=999999!!! \text{I do not know how this works. But this is a special number!!!}\\142857*1, ~142857*2,~142857*3,~142857*4~142857*5~142857*6~\\\text{all have the same digits shifted!!! But 142857 * 7=999999!!!}\\~ Logical solution. Well the logical way is as follows. x, y, z are unknown digits, xyz means 100+10y+z. After the operation, the first digit is 7. So before the operation, first two digits must be some thing more that 14. 14x * 5=714. \color{#D61F06}{\text{Logical solution.}}\\~\text{Well the logical way is as follows.}\\\text{ x, y, z are unknown digits, xyz means 100+10y+z. }\\ \text{After the operation, the first digit is 7. So before the operation,} \\ \text{first two digits must be some thing more that 14. 14x * 5=714.} \\ So x is only 2 so that we can have 7 14. But 4 would come if next digit is 8, (8*5=40). So the number likely is 142857. Check:- 142857*5 is equal to 714285. \text{So x is only 2 so that we can have }7 \color{#D61F06}{1} 4. \\ \text {But 4 would come if next digit is 8, (8*5=40).} \\ \text {So the number likely is 142857. Check:- 142857*5 is equal to 714285.}

too lenghty try to minmize your steps

Rishi Sharma - 6 years, 1 month ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...