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1 solution
Hello, as y= x^2 / x-8,(differentiate(quotient rule)), y'= x^2 - 16x / (x-8)^2,
for minimum value,
y'=0, x^2 - 16X / (x - 8) ^2 =0,
x^2 - 16x=0, x(x-16)=0, x=0 or x=16,as stated x>8, take x=16,
minimum value=y=(16)^2 / 8 =32,
thanks...