Let be an equilateral triangle with perimeter . Let be the midpoint of . Let and be points on and respectively, such that the perimeter of triangle is at a minimum.
Find this minimum perimeter.
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The shortest length or distance of L M N will be the complete path traveled by light. Treating the internal sides of △ A B C as mirrors, this occurs when a beam of light starting from M , hitting the mid-point of A B at an incident angle of 3 0 c i r c leaving with a reflective angle of 3 0 c i r c ; again hitting and leaving the mid-point of B C at 3 0 c i r c before returning to point M . Therefore, L and N are mid-points of A B and B C . and △ L M N is an equilateral triangle with side length of 4 cm and hence its perimeter 4 × 3 = 1 2 .