Minimum Value

Algebra Level 3

If three positive real numbers a,b,c are in A.P, then find the minimum value of b if a b c = 8 abc=8

8 2 1 4

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1 solution

Sujoy Roy
Aug 2, 2015

a + b + c 3 ( a b c ) 1 / 3 \frac{a+b+c}{3}\ge (abc)^{1/3} or, b + 2 b 3 ( 8 ) 1 / 3 \frac{b+2b}{3}\ge (8)^{1/3} or, b 2 b\ge 2 .

Thus, minimum value of b b is 2 \boxed{2} .

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