Minimum value of F(X)
Geometry
Level
pending
What is the minimum value of F(X) = Sin(X) such that ( 2* π ) /9 <= X <= 5* π /6
1
0.642
0
0.5
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1 solution
Sin(X) is increasing in the interval 0 <= X <= π/2 and decreasing in the interval π/2 <= X <= π
Hence Sin(X) is also increasing in the interval (2 * π)/9 <= X <= π/2 and decreasing in the interval π/2 <= X <= 5* π /6. Hence the minimum of F(X) in the interval
( 2* π ) /9 <= X <= 5* π /6 occurs either when X = (2 * π)/9 or when X = 5* π /6. F((2 * π)/9) = 0.64 , F(5* π /6) = 0.5. Therefore the minimum value of F(X) = Sin(X)
such that ( 2* π ) /9 <= X <= 5* π /6 is equal to 0.5.