Mininizing tension

A heavy horizontal girder of length $L$ has several objects hung from it.It is supported by a frictionless pivot at one end and a cable of neglegible weight that is attached to a I beam, at a point directly above girder's center at height $H$ . Where should the other end of the cable be attached to the girder so that the cable’s tension is minimum (Hint: In evaluating and presenting your answer, don’t forget that the maximum distance of the point of attachment from the pivot is the length $L$ of the beam.)?

The answer can be expressed as $\dfrac{p}{q}.H^x.L^y$

Find $p+q+x+y$

Note

• Please upload a solution.

• $p,q$ are coprime.

• what could be the case if $h \leq \dfrac{L}{2}$