Find the image of the point (3,8) with respect to the mirror x+3y=7
If your answer is (a,b), enter the answer as abs(a)+abs(b)
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Slope of normal to the mirror is 3, and the normal through the point would be y − 8 = 3 × ( x − 3 ) . . . . > y = 3 x − 1
The normal and the mirror intersect at (1, 2). ..>
(1, 2) is the midpoint of the point and its image. thus the image is (- 1, - 4)
5