The quantity Z is a complex number which satisfies the following equation:
Z 2 + ∣ Z ∣ 2 − 3 + 5 j = 0
What is ∣ Z ∣ ?
Details and Assumptions:
1)
j
=
−
1
2)
∣
⋅
∣
denotes the magnitude of a complex number
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Z= √ ( 2 3 ) - √ 6 5 j . So ∣ Z ∣ = √ ( 3 1 7 ) = 2 . 3 8 0 4 7 6
Is this the only solution?
No. There is another solution also. But that does not change the answer.
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Can you prove this assertion?
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Take Z=a+bj, substitute in the given equation, compare the real and imaginary parts.
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Let Z = X + i Y with X , Y real. Then Z 2 = X 2 + 2 i X Y − Y 2 and ∣ Z ∣ 2 = X 2 + Y 2 .
Considering the real parts of the equation,
X 2 − Y 2 + X 2 + Y 2 − 3 = 0
so X 2 = 2 3 . Considering imaginary parts,
2 X Y + 5 = 0
so Y 2 = 6 2 5 .
Hence ∣ Z ∣ 2 = X 2 + Y 2 = 3 1 7 and ∣ Z ∣ = 3 1 7 .