Mixture Problem

Algebra Level pending

An alloy of lead and nickel weighs two pounds. The alloy weighs 28.8 ounces in water. Lead loses 1 11 \frac{1}{11} of its weight and nickel loses 1 9 \frac{1}{9} of its weight in water. How much ounces of lead is in the alloy?


The answer is 17.6.

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1 solution

x x = weight of lead in the alloy

y y = weight of nickel in the alloy

o n e one p o u n d pound = = 16 16 o u n c e s ounces

x + y = 32 x+y = 32

y = 32 x y = 32 - x ----equation (1)

10 11 \frac{10}{11} x + x + 8 9 \frac{8}{9} y = y = 28.8 28.8 --- equation (2)

Substitute equation (1) in equation (2)

10 11 \frac{10}{11} x + 8 9 x + \frac{8}{9} ( 32 x ) = 28.8 (32 - x) = 28.8

10 11 \frac{10}{11} x x + + 256 9 \frac{256}{9} 8 9 \frac{8}{9} x x = 28.8 = 28.8

x = 17.6 x = 17.6 o u n c e s ounces

Can you clarify wat it means that "Lead loses 1/11 of its weight in water"?

Also, you should state the number of ounces in a pound.

Calvin Lin Staff - 4 years, 5 months ago

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That means that the weight of lead in water decreases by 1/11 of it's weight in air. So it's weight in water is 10/11 of its weight in air.

A Former Brilliant Member - 4 years, 5 months ago

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