Mobius, phi and 2016

Given that μ ( n ) = 1 \mu(n)=-1 ϕ ( n ) = 2016 \phi(n)=2016 find the sum of the values of odd integer n. note: ϕ ( n ) \phi(n) is eulers totient function and μ ( n ) \mu(n) is the mobius function.


The answer is 13425.

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