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Calculus Level 3

x 3 d x = ? \large \int \left| x \right|^3 \, dx = \ ?

Note : C C is the arbitrary constant of integration.

None of these choices x 4 4 + C - \dfrac{x^4}{4} + C x 4 4 + C \dfrac{x^4}{4} + C x 3 3 + C \dfrac{x^3}{3} + C

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1 solution

x 3 d x = { x 4 4 + C ; x 0 x 4 4 + C ; x 0 \large ~~\int|x|^3dx = \begin{cases} \dfrac{x^4} 4 +C&&;&& x~\geq~ 0~~ \\ -\dfrac{x^4} 4 +C&&;&& x~\leq~ 0 \end{cases}

It can't be negative. This function is positive for whatever x. Make the substitution x = x 2 \ |x|= \sqrt{x^2} in the integral and you'll get x 4 4 + C \ \frac{x^4}{4} + C

Leonardo de Araujo - 5 years, 7 months ago

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The function, not its integral is positive.

Niranjan Khanderia - 5 years, 7 months ago

Hello, can u explain why if x<0 then it is negative? I thought that it would be positive because if we put that on a graph, the curve will be above the x axis always. Thanks

Ivan Martinez - 5 years, 8 months ago

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There are two possibilities for the function. I t c o u l d b e + x 3 t h e n i n t e g r a l i s p o s i t i v e . O R i t c o u l d h a v e b e e n x 3 , t h e i n t e g r a l i s n e g a t i v e . This is how it is solved. Sorry did not see your comment early. It~could~be~+x^3~then~integral~is~positive. \\ OR~it ~could~have~been~ - x^3, ~the~ integral ~is~ negative.\\ \text{This is how it is solved. Sorry did not see your comment early. }

Niranjan Khanderia - 5 years, 7 months ago

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