Model Rockets Can Go Pretty Fast

Note that Change in momentum = Impulse

m(v-u)= p. 0.050kg (v-0) = 10 Ns Hence v = 10 Ns/0.050 kg = 200 m/s

Inicialmente, devemos encontrar o tempo decorrido.

$\\ I = F \times \Delta t \\\\ I = \left ( P \times g \right ) \times \Delta t \\\\ 10 = \left ( 0.05 \times 9,8 \right ) \times \Delta t \\\\ 0.49\Delta t = 10 \\\\ \Delta t = 20,4 \, s$

Com isso,

$\\ V = V_o + \alpha \times t \\\\ V = 0 + 9.8 \times 20.4 \\\\ \boxed{V = 199.92 \; \text{m/s}}$

$I = \triangle P$ which $P_{1}=mV$ and $P_{2}=m0$ so, $10=0.05V-0, V = 200\frac{m}{s}$

Impulse is equal to mv-mu therefore mass is 50gm , so we should convert it into kg so we get 0.05kg substituting it into equation we will get v-u is equal to 200

impulse=change in momentum 10=50 x 10^(-3) x v hence v=300m/s

The equation for momentum is mass \times velocity . So to find the velocity we must divide 10 Newton Seconds (the SI unit of momentum) by 0.05 kg to get 200 m/s.

We know if F = kg m/s^2, We must thinks that F = (mass x velocity)/time --->then, I = F.t ---> I = m.v/t . t ---> I = mv ----> v = I/m ---> v = 10/(0.05) m/s = 200 m/s. Answer : 200

Yo,as for this just use that impulse formula that is Ft-mv-mu,given m=0.05kg,then u=0m/s,

Ft=mv-mu=10 m(v-u)=10 0.05(v-0)=10 v=10/0.05=200 m/s....thanks...

O impulso é igual a quantidade de movimento

I=Q

10=0,05*V

V=200m/s

Impulse = Mass * time. So, Impulse = $10 N*s$ , mass = 0.05 kg, time = ???.

time:= $\frac{impulse}{mass}$ = $\frac{10}{0.05}$ = $\frac{10*100}{5}$ = $\boxed{2E+2}$ seconds or $\boxed{200}$ seconds

m = 50 g p = 10 N.s v = ? (p/m)

Since p is N.s, hence it is also kg-m/s , so you only need to convert the mass to kg. So, if m = 50 g, = .05 kg.

Substitution: v = p/m = (10 kg-m/s)/.05 kg = 200 s

Impulse equals to delta (change in) momentum = $m \times v$

so, $10 = 0.05 \times v$

$v = 200$

10/50*10E-3=200