Modular Argument!

Algebra Level 4

If a = b |a|=|b|^{'} and a r g ( a b ) arg(\frac{a}{b}) = = π \pi , then what is the value of a + b a+b ?

Note - a a and b b are complex numbers !!!!!

-1 e e e^{e} e e \infty e π e^{\pi} e i e^{i} 1 0

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Karan Shekhawat
Apr 14, 2015

It must be Level-1 or 2 (max) Problem....

Gagan Raj
Apr 14, 2015

Given , a = b |a|=|b| and a r g ( a b ) = π arg(\frac{a}{b})=\pi

a r g ( a ) a r g ( b ) = π arg(a)-arg(b)=\pi

a r g ( a ) = π + a r g ( b ) arg(a)=\pi+arg(b)

If , b = r e i θ b=re^{i\theta}

a = r e i ( π + θ ) a=re^{i(\pi+\theta)}

a = r e i π . e i θ a=re^{i\pi}.e^{i\theta}

a = r e i θ a=-re^{i\theta}

a = b a=-b

a + b = 0 a+b=0

Hence , the answer is 0 0 .

1 pending report

Vote up reports you agree with

×

Problem Loading...

Note Loading...

Set Loading...