Modular arithematic

Level 1

Find the remainder when 2 33 2^{33} is divided by 17 17 .

9 2 4 15

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1 solution

Chew-Seong Cheong
Apr 19, 2018

2 33 2 4 × 8 + 1 2 ( 1 6 8 ) 2 ( 17 1 ) 8 2 (mod 17) \large 2^{33} \equiv 2^{4\times 8+1} \equiv 2(16^8) \equiv 2(17-1)^8 \equiv \boxed{2} \text{ (mod 17)}

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