If , where 'p' belongs to prime numbers but 'p' is not equal to '2 or 3'. Find largest 'a' which is satisfied for all conditions.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
p+1 and p-1 are always divisible by 2 , 3 and 4. i.e. p=7 p+1=8 ( divisible by 2 and 4.) p-1=6 ( divisible by 2 and 3.) Therefore, (p^2)-1 divisible by 24{always}. (p^2) equivalent to 1 (mod 24) Hence proved.