Mole concept 1

Chemistry Level 3

To keep fit, an astronaut needs to burn 34.2 grams of sucrose C X 12 H X 22 O X 11 \ce{C_{12}H_{22}O_{11}} per hour in his body. How many grams of oxygen would the astronaut need in a space shuttle, in order to burn the sucrose to have enough energy for 1 day?


Image Credit: Wikimedia NearEMPTiness .


The answer is 921.6.

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1 solution

Aditya Paul
Feb 2, 2015

342 g sucrose needs 12 × ( 16 × 2 ) 12 \times (16 \times 2) oxygen in 1 hour.
34.2 g sucrose needs 12 × ( 16 × 2 ) ÷ 10 12 \times (16 \times2)\div10 oxygen in 1 hour.
oxygen needed for 24 hours is 24 × 12 × ( 16 × 2 ) ÷ 10 = 921.60 g . 24 \times 12 \times (16 \times 2)\div10 = 921.60\text{ g}.

342g of sucrose contains 176g of oxygen. Therefore 34.2 g contains 17.6g of oxygen. This 17.6g of oxygen supplies emergy for 1 hour. 24 hrs require 24x17.6 g of oxygn = 422.4g of oxygen.

This may be the correct answer.

anand douglas - 5 years, 7 months ago

wait, why have you taken 12? isn't the molecular mass of oxygen 16?

Ishita Bhatia - 6 years, 4 months ago

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it is coefficent of balancing eqution

Ignite Infinity - 5 years, 9 months ago

Doesn't it takes 3 Mol of Oxygen to fully react ( oxidize) 1 mol of sucrose ? 34.2 g of sucrose is 0.1 Mol . Hence it takes 0.3 mol of Oxygen to fully combust a mole of sucrose. 0.3 mol of oxygen is 4.7998 grams. in 24 hours, he would need 4.7998 * 24= 115.19 grams of oxygen.

A Former Brilliant Member - 5 years, 3 months ago

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Why only 3 mol? What is your chemical equation?

C 12 H 22 O 12 + 3 O 2 = C_{12} H_{22} O_{12} + 3 O_2 =

Calvin Lin Staff - 5 years, 3 months ago

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Yeah it takes 12 mols of Oxygen to fully combust 1 mol of sucrose. 34.2 g of sucrose contains 0.1 mol. Therefore it will take 1.2 mols of O2 which turns out to be 1.2 * 31.9988=38.398 g. In 24 hours that is equivalent to 921.56

So the answer is correct.

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Edit

A Former Brilliant Member - 5 years, 3 months ago

Why have you multiplied 16 by 3? should not it be 12 * (16 * 2 ) ?

Khalak Mahadeviya - 5 years, 8 months ago

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